n=int(input())
a=list(map(int,input().split()))
next=[-1]*n
used=[0]*n
for i in range(n):
for j in range(n):
if 2*a[i]==a[j] or a[i]==a[j]*3:
next[i]=j
used[j]=1
break
x=used.index(0)
while x>=0:
print(a[x],end=" ")
x=next[x]
print()
1062B - Math | 1294C - Product of Three Numbers |
749A - Bachgold Problem | 1486B - Eastern Exhibition |
1363A - Odd Selection | 131B - Opposites Attract |
490C - Hacking Cypher | 158B - Taxi |
41C - Email address | 1373D - Maximum Sum on Even Positions |
1574C - Slay the Dragon | 621A - Wet Shark and Odd and Even |
1395A - Boboniu Likes to Color Balls | 1637C - Andrew and Stones |
1334B - Middle Class | 260C - Balls and Boxes |
1554A - Cherry | 11B - Jumping Jack |
716A - Crazy Computer | 644A - Parliament of Berland |
1657C - Bracket Sequence Deletion | 1657B - XY Sequence |
1009A - Game Shopping | 1657A - Integer Moves |
230B - T-primes | 630A - Again Twenty Five |
1234D - Distinct Characters Queries | 1183A - Nearest Interesting Number |
1009E - Intercity Travelling | 1637B - MEX and Array |